F(x)=x^2+3x+12

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Solution for F(x)=x^2+3x+12 equation: 



(F)=F^2+3F+12

We move all terms to the left:

(F)-(F^2+3F+12)=0

We get rid of parentheses

-F^2+F-3F-12=0

We add all the numbers together, and all the variables

-1F^2-2F-12=0

a = -1; b = -2; c = -12;
Δ = b2-4ac
Δ = -22-4·(-1)·(-12)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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